a. 7x^2-7xy-5x+5y
b. x^2-6x+9-9y^2
c. 2xy+3z+6y+xz
d. a^4+6a^2+9-36t^2
e. a^2+2ab+b^2-x^2+2xy-y^2
g. x^2-4x^2y^2+y^2+2xy
h. 25-a^2+2ab-b^2
m. x^2+2xy+y^2-xz-yz
n. a^3+3a^2+3a+1-a-1
GIÚP MK VỚI Ạ
MK ĐANG CẦN GẤP Ạ.
a. 7x^2-7xy-5x+5y b. x^2-6x+9-9y^2 c. 2xy+3z+6y+xz d. a^4+6a^2+9-36t^2 e. a^2+2ab+b^2-x^2+2xy-y^2 g. x^2-4x^2y^2+y^2+2xy h. 25-a^2+2ab-b
By Adeline
Đáp án:
Giải thích các bước giải:
$a,7x^2-7xy-5x+5y$
$=7x(x-y)-5(x-y)$
$=(7x-5)(x-y)$
$b,x^2-6x+9-9y^2$
$=(x-3)^2-(3y)^2$
$=(x-3-3y)(x-3+3y)$
$c,2xy+3z+6y+xz$
$=2y(x+3)+z(x+3)$
$=(2y+z)(x+3)$
$d,a^4+6a^2+9-36t^2$
$=(a^2+3)-(6t)^2$
$=(a^2+3-6t)(a^2+3+6t)$
$e,a^2+2ab+b^2-x^2+2xy-y^2$
$=(a+b)^2-(x-y)^2$
$=(a+b-x+y)(a+b+x-y)$
$g,x^2-4x^2y^2+y^2+2xy$
$=(x+y)^2-(2xy)^2$
$=(x+y-2xy)(x+y+2xy)$
$=(x-y)^2(x+y)^2$
$h,25-a^2+2ab-b^2$
$=5^2-(a-b)^2$
$=(5-a+b)(5+a-b)$
$m.x^2+2xy+y^2-xz-yz$
$=(x+y)^2-z(x+y)$
$=(x+y)(x+y-z)$
$n,a^3+3a^2+3a+1-a-1$
$=(a+1)^3-(a+1)$
$=(a+1)(a^2+2a+1-1)$
$=(a+1)(a^2+2a)$
$=(a+1)(a+2)a$
a. $7x^{2}$ – 7xy -5x + 5y
= 7x(x-y) -5(x-y)
=(x-y) (7x-5)
b. $x^{2}$ -6x + 9 -$9y^{2}$
= $(x-3)^{2}$ – $(3y)^{2}$
= (x-3-3y)(x-3+3y)
c. 2xy + 3z +6y + xz
=2y(x+3) + z(x+3)
=(x+3)((2y+z)
d. $a^{4}$ + $6a^{2}$ + 9 – $36t^{2}$
= $(a^{2}+ 3)^{2}$ – $(6t)^{2}$
= ($a^{2}$ +3 -6t)($a^{2}$ +3 +6t)
e. $a^{2}$ + 2ab + $b^{2}$ -$x^{2}$ +2xy – $y^{2}$
= $(a+b)^{2}$ – $(x+y)^{2}$
= (a+b-x-y)(a+b+x+y)
g. $x^{2}$ – 4$x^{2}$ $y^{2}$ + $y^{2}$ +2xy
= $(x+y)^{2}$ – $(2xy)^{2}$
= (x+y-2xy)(x+y+2xy)
h.25 -$a^{2}$ + 2ab – $b^{2}$
= -($a^{2}$ – 2ab + $b^{2}$ -25 )
= -($(a-b)^{2}$ -$5^{2}$ )
= -[(a-b-5)(a-b+5)]