K—(1)—->K2O—–(2)—->KOH—–(3)—->K2CO3—-(4)—–>KCl
(1):
(2):
(3):
(4):
giúp mình vs ạ :<
K—(1)—->K2O—–(2)—->KOH—–(3)—->K2CO3—-(4)—–>KCl (1): (2): (3): (4): giúp mình vs ạ :<
By Cora
By Cora
K—(1)—->K2O—–(2)—->KOH—–(3)—->K2CO3—-(4)—–>KCl
(1):
(2):
(3):
(4):
giúp mình vs ạ :<
1: $4K + O_2 → 2K_2O$
2: $K_2O + H_2O → 2KOH$
3: $2KOH + CO_2 → K_2CO_3 + H_2O$
4: $K_2CO_3 + 2HCl → 2KCl + CO_2 + H_2O$
Đáp án:
$1/ 4K + O2 -> 2K2O$
$2/ K2O + H2O -> 2KOH$
$3/ 2KOH + CO2 -> K2CO3 + H2O$
$4/ K2CO3 + 2HCl -> 2KCl + CO2 + H2O$